Re: [xslt] Problem with creating namespace in the stylesheet

[Jirka Kosek <jirka kosek cz>]

Petr Novak wrote:

> That is problem, because I don't know this namespace - it is parsed from the
> processing XML document. Exactly the situation is:
>
> <xsl:stylesheet version="1.0"
>  xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>  xmlns:xslo="http://www.w3.org/1999/XSL/TransformAlias";
>  xmlns:schema="http://relaxng.org/ns/structure/1.0";>
>
> <xsl:import href="relaxng-core.xsl"/>
> <xsl:output method="xml" encoding="iso-8859-1" indent="yes"/>
> <xsl:strip-space elements="*"/>
> <xsl:namespace-alias stylesheet-prefix="xslo" result-prefix="xsl"/>
>
> <xsl:template match="/">
> 	<!-- Now I take the namespace -->
> 	<xsl:variable name="netopeerns" value="schema:grammar/@ns"/>
>
> 	<!-- Now I create the <xslo:stylesheet> element -->
> 	<xsl:element name="xslo:element">
> 		<!-- Now it is created the <xslo:stylesheet> element. I need to add the namespace to it with "netopeer" prefix and the same value as the value of the $netopeerns is -->
> 		<!-- e.g., if the value of the $netopeer variable is "http://www.liberouter.org";, I need to obtain output as a: <xslo:stylesheet xmlns:netopeer="http://www.liberouter.org"/> -->
>
> 		<!-- Processing the rest of the document... -->

I still don't see your problem. You can generate your elements using:

<xsl:element name="myElementInNetoPeerNS" namespace="{$netopeerns}">
  ...
</xsl:element>

Namespace declaration will be added automatically in this case. Does it 
solve your problem?

				Jirka

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