Re: [xml] xmlGetNodePath and default namespaces
- From: Daniel Veillard <veillard redhat com>
- To: Andrew Jackson <ajj nist gov>
- Cc: xml gnome org
- Subject: Re: [xml] xmlGetNodePath and default namespaces
- Date: Tue, 4 Mar 2008 11:15:47 -0500
On Tue, Mar 04, 2008 at 11:02:56AM -0500, Andrew Jackson wrote:
I've been writing some code using the version of libxml2 that is
shipped with OS X 10.4 and using xmlGetNodePath to list the elements
in my files (which use a default namespace). I recently switched to
the latest version and now, instead of a listing of names I get
things like /*/*.
Looking at the archives and the code I see that in tree.c there is a
comment (around line 4318) that says:
* We cannot express named elements in the default
* namespace, so use "*".
I understand that this change was to ensure that XPath useable
strings were returned, but that doesn't do me any good as I don't
know what I'm getting back if I use the string since I don't know
what the element is.
How should I go about extracting the names of the elements?
The name is part of the node structure for elements, attributes, etc...
so if elem->type is XML_ELEMENT_NODE you can get them as:
Red Hat Virtualization group http://redhat.com/virtualization/
Daniel Veillard | virtualization library http://libvirt.org/
veillard redhat com | libxml GNOME XML XSLT toolkit http://xmlsoft.org/
http://veillard.com/ | Rpmfind RPM search engine http://rpmfind.net/
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