Re: [xml] Simple parsing XML question...

["Lav Mehrotra" <l mehrotra zensar com>]

Nima ,

 

Remember also to free the returned string using xmlFree() as it is allocated on heap via xmlNodeListGetString()

 

xmlChar* pszNodeContent = NULL;

pszNodeContent = xmlNodeListGetString(m_ptrXMLDoc,ptrCurrXMLNode->children,1);

if (pszNodeContent)

{

            printf(“Value of <pic_file>  = %s”, (const char*)pszNodeContent);

            xmlFree(pszNodeContent);

            pszNodeContent = NULL;

}

 

-- Lav

 

---

From: Lav Mehrotra
Sent: Tuesday, June 10, 2008 11:56 AM
To: 'Nima Tiran'
Cc: xml gnome org
Subject: RE: [xml] Simple parsing XML question...

 

Nima ,

 

Plz use the following API()

 

xmlNodeListGetString(xmlDocPtr doc , xmlNodePtr list , int inline )

 

Get the (xmlDocPtr doc) from xmlParseFile(const char* filename) API or xmlParseMemory(const char* buffer , int size)

 

Get the Current (xmlNodePtr list) for ur node  <pic_file> by traversing the DOM Document Tree , until u encounter a node with  xmlNodePtr->name as same as pic_file  ( Take the help of xmlStrcmp() API ) . Say this node is xmlNodePtr pXmlNodePicFile

 

Once u have this pXmlNodePicFile u cannot blindly use pXmlNodePicFile->content as the TEXT Content MyPicFileName.pdf is also a child node of  the pXmlNodePicFile

 

So pass the 1^st child of pXmlNodePicFile to xmlNodeListGetString() API like this

 

xmlNodeListGetString(doc, pXmlNodePicFile->children , 1)

 

Regds,

 

Lav

 

---

From: xml-bounces gnome org [mailto:xml-bounces gnome org] On Behalf Of Nima Tiran
Sent: Tuesday, June 10, 2008 3:11 AM
To: xml gnome org
Subject: [xml] Simple parsing XML question...

 

Hi  all,

 

I'm newbie here and got a simple question:

 

I'm parsing an XML file and having a node like:

 <pic_file>MyPicFileName.pdf</pic_file>   

 in  XML file, just wondering how can I retrieve "MyPicFileName" from this node?

 

Thnx

Nima

 

 

 

 

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