Re: [xml] Does libxml2 create nodes on-the-fly?

[Andreas Pakulat <apaku gmx de>]

On 24.06.06 09:12:47, Daniel Veillard wrote:
> > (though I'm not familiar with libxml2's C Interface, nor the
> > Python-C-Bridge-Stuff in general)...
>
>   Should be fairly simple, make a C python binding routine based on
> existing ones in python/libxml.c , give it a significant name,
> change the beginning to expect 2 python obect references as arguments,
> see type.h to see how the C object is attached, get the two xmlNodePtr
> associated. Compare them, and return an python 0 or 1, then register
> the new routine at the end of libxml.c

I had a shot now and also found xmlCore in libxml.py, where I could
provide __eq__ and __ne__. However somehow comparing the xmlNodePtr's
doesn't really work. Even for unequal python xmlNode's a

xmlNodePtr1 == xmlNodePtr2 

returns true.

And I'm stuck there now, because I don't really know what else I could
use to compare the nodes... See Bug number 345779 for the patches.

Andreas

-- 
You don't become a failure until you're satisfied with being one.