[xml] XPath and DTD default values


I have a question about the XPath implementation.
I have tried to get the default attributes from the DTD:s to work with the XPath lookups. I am very new to libxml, so if there is a very well known answer, I'm sorry...

Consider the following document:

<?xml version="1.0"?>
<!DOCTYPE root SYSTEM "root.dtd" [
<!ATTLIST elem test CDATA "nothing">
<!ELEMENT root (elem)>
<elem test="something">data3</elem>

with this code:

void doXPath(xmlDocPtr doc,xmlChar* xpathExpr)
  xmlXPathContextPtr xpathCtx = xmlXPathNewContext(doc);
  xmlXPathObjectPtr xpathObj = xmlXPathEvalExpression(xpathExpr,xpathCtx);
  xmlNodeSetPtr nodes = xpathObj->nodesetval;
  for (int i = 0; i < nodes->nodeNr; i++) {
     if (nodes->nodeTab[i]->type == XML_ELEMENT_NODE) {
        xmlNodePtr node = nodes->nodeTab[i];
        xmlChar* pProp = xmlGetProp(node,BAD_CAST "test");
        xmlChar* pContent = xmlNodeGetContent(node);
std::cout << "Node: " << node->name << ", Data: " << pContent << ", test = " << pProp << endl;
        xmlFree((void*) pContent);
        xmlFree((void*) pProp);

doXPath(doc,(xmlChar*) "//root/*");
gives me:
Node: elem, Data: data1, test = nothing
Node: elem, Data: data2, test = nothing
Node: elem, Data: data3, test = something

So, xmlGetProp works great, giving me the default value of "nothing"

doXPath(doc,(xmlChar*) "//root/*[ test=\"something\"");
gives me:
Node: elem, Data: data3, test = something

Still, as expected.

doXPath(doc,(xmlChar*) "//root/*[ test=\"nothing\"");
gives me no results...

Am I wrong in expecting xpath to work with default values, or can anybody help me out?

Jonas Holmberg

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