Re: [xml] how to read from network by xmlReadFile

["中井和広" <nakai kazuhiro sharp co jp>]

In a message dated Wed, 24 Nov 2004 19:56:30 +0900,
 <veillard redhat com> wrote:
veillard>> 
veillard>> doc = xmlReadFile("http://localhost/resource/test.xml";)
veillard>
veillard>  xmlReadFile takes 3 arguments. I don't believe your actually tried th
Oh. excuse me.
in fact, my codes are

conf_doc=cgi_readAgentDB("file:///mydir/template/agent_db.xml");
.....

xmlDocPtr cgi_readAgentDB(const char *filename)
{
  xmlDocPtr doc;
......
  doc = xmlReadFile(filename,NULL,0);
......
......
  return doc;
}

and. I forgot other argument, when i post that question.
very sorry.

veillard>> but, error message (fail to load HTTP resource) returns.
veillard>
veillard>  Works for me
veillard>
veillard>paphio:~ -> python
veillard>Python 2.2.3 (#1, Aug  8 2003, 08:44:02)
veillard>[GCC 3.2.3 20030502 (Red Hat Linux 3.2.3-13)] on linux2
veillard>Type "help", "copyright", "credits" or "license" for more information.
veillard>>>> import libxml2
veillard>>>> doc = libxml2.readFile('http://veillard.com/test.xml', None, 0)
veillard>>>> doc.serialize()
veillard>'<?xml version="1.0" encoding="iso-8859-1"?>\n<doc/>\n'
veillard>>>>
veillard>
veillard>either your libxml2 is compiled without HTTP support, or the HTTP

Is Supporting HTTP optional?
My. platform is gentoo. and I do nothing to libxml2, but emerge them.

Thank you.
I'll read libxml2 installing manual well again.   






_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/
MAIL : nakai kazuhiro sharp co jp
_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/