Re: [xml] how to read from network by xmlReadFile
- From: Daniel Veillard <veillard redhat com>
- To: ääåå <nakai kazuhiro sharp co jp>
- Cc: xml <xml gnome org>
- Subject: Re: [xml] how to read from network by xmlReadFile
- Date: Wed, 24 Nov 2004 05:56:30 -0500
On Wed, Nov 24, 2004 at 03:37:05PM +0900, ääåå wrote:
Thu, 01 Jan 1970 09:00:00 +0900
hellow.
I read the short description of of xmlReadFile at parser Manual of
'Reference Manual for libxml2',that say 'parse an XML file from the
filesystem or the network.'
And so, I tried to read the xml file from my local network, by call
the function like as follows.
doc = xmlReadFile("http://localhost/resource/test.xml")
xmlReadFile takes 3 arguments. I don't believe your actually tried that
code or if you did your compiler is severely broken.
but, error message (fail to load HTTP resource) returns.
Works for me
paphio:~ -> python
Python 2.2.3 (#1, Aug 8 2003, 08:44:02)
[GCC 3.2.3 20030502 (Red Hat Linux 3.2.3-13)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
import libxml2
doc = libxml2.readFile('http://veillard.com/test.xml', None, 0)
doc.serialize()
'<?xml version="1.0" encoding="iso-8859-1"?>\n<doc/>\n'
either your libxml2 is compiled without HTTP support, or the HTTP
resource is not available/not XML or your code just didn't work for
other reasons.
Daniel
--
Daniel Veillard | Red Hat Desktop team http://redhat.com/
veillard redhat com | libxml GNOME XML XSLT toolkit http://xmlsoft.org/
http://veillard.com/ | Rpmfind RPM search engine http://rpmfind.net/
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