Re: [xml] Finding the root node from a DTD

[Daniel Veillard <veillard redhat com>]

On Tue, Mar 25, 2003 at 07:33:08PM -0800, Quandary wrote:
> I'm trying to fill in 'root_node' in the following
> code fragment:
>
> xmlCreateIntSubset(docpDocument, root_node, NULL,
> (xmlChar*) chpFileName);
>
> If I parse the DTD file beforehand (with xmlParseDtd()
> ), is there any way for me to determine what the
> name/root element is for that DTD?
>
> I would -think- that there would be a solution to this
> problem that is more generic than hard-coding
> 'root_node' or asking the user for the root element
> every run, but I am just not seeing it.

  If you have the document, then pass its root node name
use xmlDocGetRootElement()
     - if root->ns == NULL || root->ns->prefix == NULL
       then pass root->name
     - else root->ns->prefix':'root->name

Daniel

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