[xml] Finding the root node from a DTD
- From: Quandary <ai2097 yahoo com>
- To: xml gnome org
- Subject: [xml] Finding the root node from a DTD
- Date: Tue, 25 Mar 2003 19:33:08 -0800 (PST)
Hi all. I've been tearing hair for a couple days now
trying to solve this (seemingly) simple problem;
hopefully someone here can point out what I'm
overlooking...
I'm trying to fill in 'root_node' in the following
code fragment:
xmlCreateIntSubset(docpDocument, root_node, NULL,
(xmlChar*) chpFileName);
If I parse the DTD file beforehand (with xmlParseDtd()
), is there any way for me to determine what the
name/root element is for that DTD?
I would -think- that there would be a solution to this
problem that is more generic than hard-coding
'root_node' or asking the user for the root element
every run, but I am just not seeing it.
Your time and comments are appreciated,
-- Quandary
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