Re: int (utf-8) to Glib::ustring

[Spazzatura.Live <kharhonte hotmail com>]

Right! However it's really weird there isn't an embedded function! 
(leastwise for converting a integer value...)

Il 04/12/2011 13:40, Kjell Ahlstedt ha scritto:
> 2011-12-03 15:29, Spazzatura.Live skrev:
> > char *utf8hex_to_str(const char *utf8hex)
> > {
> >     const size_t utf8_char_size_t = strlen(utf8hex)/2 + 1;
> >
> >     char *utf8_char = new char[utf8_char_size_t];
> >
> >     int utf8int;
> >
> >     sscanf(utf8hex, "%8x", &utf8int);
> >
> >     utf8_char[utf8_char_size_t-1] = '\0';
> >
> >     for(size_t i=0;i<utf8_char_size_t-1;i++)
> >     {
> >         utf8_char[i] = (char)(utf8int >> (8*(utf8_char_size_t-i-2)));
> >     }
> >
> >     return utf8_char;
> > }
> >
> > This should work either for 4, 3, 2 or 1 utf8 hex char.
>
> Yes, and it can be made even more general. You need not restrict 
> utf8hex to contain the representation of only one code point. (If 
> you're not used to Unicode terminology, look e.g. at Wikipedia, 
> http://en.wikipedia.org/wiki/Unicode.)
>
> char* utf8hex_to_str(const char* utf8hex)
> {
>   const size_t utf8_hex_len = strlen(utf8hex);
>   if (utf8_hex_len & 1)
>   {
>     return 0; // Error. Odd number of hex digits.
>   }
>   const size_t utf8_char_len = utf8_hex_len/2;
>   char* utf8_char = new char[utf8_char_len+1];
>
>    for (size_t i = 0; i < utf8_char_len; i++)
>   {
>     int utf8int;
>     sscanf(utf8hex+2*i, "%2x", &utf8int);
>     utf8_char[i] = (char)utf8int;
>   }
>   utf8_char[utf8_char_len] = '\0';
>
>   return utf8_char;
> }