Re: int (utf-8) to Glib::ustring

[Spazzatura.Live <kharhonte hotmail com>]

char *utf8hex_to_str(const char *utf8hex)
{
    const size_t utf8_char_size_t = strlen(utf8hex)/2 + 1;

    char *utf8_char = new char[utf8_char_size_t];

    int utf8int;

    sscanf(utf8hex, "%8x", &utf8int);

    utf8_char[utf8_char_size_t-1] = '\0';

    for(size_t i=0;i<utf8_char_size_t-1;i++)
    {
        utf8_char[i] = (char)(utf8int >> (8*(utf8_char_size_t-i-2)));
    }

    return utf8_char;
}

This should work either for 4, 3, 2 or 1 utf8 hex char.

Il 02/12/2011 23:59, Spazzatura.Live ha scritto:
> First of all, i want really to thank you very much, because the gtkmm 
> documentation is really poor and the library itself lacks of a lot of 
> necessary functions; this morning, i was going to read all the 
> documentation of Unicode, utf8 and utf16 to work with raw data and do 
> the conversion functions by myself, you saved me from this hard work.
>
> I'm reading the Thunderbird addressbook and i'm creating a mork parser 
> (because the one i found didn't recognized the vocal with accent (and 
> now i know why...)). In the mork file, the "non latin base" character 
> are written in utf8 hex (like ò=$C3$B2) so i was getting mad to know 
> how to convert it (without using a really "un-chic" and bad functional 
> table).
>
> However it works like i wanted to. Thanks again.
>
> Regards,
> Stefano
>
> Il 02/12/2011 17:08, Kjell Ahlstedt ha scritto:
> > 2011-12-02 10:02, Spazzatura.Live skrev:
> > > Hi everyone.
> > >
> > > I have an hex representation (in a string) of a 2 byte UTF-8 char.
> > >
> > > When i try to use g_unichar_to_utf8(), it converts a UTF-16 value to 
> > > a gchar *, so:
> > >
> > > 1) How can i convert UTF-8 to UTF-16 value?
> > >
> > > OR
> > >
> > > 2) How can i convert a UTF-8 value into std::string, Glib::ustring, 
> > > gchar * or char *?
> >
> > Do you mean that you have a 4-byte string, e.g. "C384", that 
> > represents a 2-byte UTF-8 character (in this case 0xc3,0x84 = U+00C4 
> > = Umlaut-A = Ä)?
> >
> > I don't know of any function that converts easily from the 4-byte 
> > string to the 2-byte string you need. Perhaps you have to use sscanf().
> >
> > const char hexstring[] = "C384"; // Perhaps read from a file
> > char utf8char[3];
> > int utf8int;
> >
> > sscanf(hexstring, "%4x", &utf8int);
> > utf8char[0] = static_cast<char>(utf8int >> 8);
> > utf8char[1] = static_cast<char>(utf8int);
> > utf8char[2] = '\0';
> >
> > This seems fairly complicated for such a simple task. Perhaps someone 
> > knows of a function that does this conversion in one step?
> >
> > Now you have your UTF-8 character in a char*. gchar is a typedef for 
> > char, so you could just as well have declared
> >   gchar utf8char[3];
> > to get a gchar*. The conversions to Glib::ustring and std::string are 
> > easy, e.g.
> >   Glib::ustring str(utf8char);
> >   std::string str(utf8char);
> >
> > To convert from UTF-8 to UTF-16, use g_utf8_to_utf16(), e.g.
> >   gunichar2* utf16 = g_utf8_to_utf16(utf8char, -1, 0, 0, 0);
> >
> > Or have I misunderstood you? In the subject line you mention "int 
> > (utf-8)", but in the first line of your message you talk about a string.
> > If you start with an int, e.g.
> >   const int utf8int = 0xc384;
> > then you skip the call to sscanf().
> >
> > If utf8int is your starting point, you have a UTF-8 value stored in 
> > an unusual way. You should perhaps check if you can avoid getting 
> > there in the first place.
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