Re: Newbie & timing issue

[Alf C Stockton <alf stockton co za>]

On Mon, 12 Jul 2004, David Necas (Yeti) wrote:

> On Mon, Jul 12, 2004 at 07:16:57PM +0200, Alf C Stockton wrote:
> > John your program required the user to click the OK button to close the
> > displayed window. Is there a way this can be done by timing. ie The display
> > window closes, without user interferance, after say 10 seconds?
>
> Again, you can use g_timeout_add(), now the function will
> call gtk_button_clicked() on the button after 10s. Just
> remember to remove the timeout function when the button is
> pressed, so it isn't run then and doesn't try to press it
> again.
David, I don't understand what you mean. The code already includes a
g_timeout_add(). Are you suggesting another call to this function?
The code currently looks like:-
#include <gtk/gtk.h>
#include <glib-2.0/glib.h>
#include <time.h>

void response_cb( GtkDialog *dialog )
    {
    gtk_widget_destroy( GTK_WIDGET( dialog ) );
    }

gboolean timeout_cb()
    {
    GtkWidget *dialog;
    struct tm *tm_ptr;
    time_t the_time;
    gchar Message[256];
    time(&the_time);
    tm_ptr = localtime(&the_time);

    g_sprintf(Message,"It is now %02d:%02d:%02d\n",
                tm_ptr->tm_hour,
                tm_ptr->tm_min,
                tm_ptr->tm_sec);
    dialog = gtk_message_dialog_new( NULL, 0, GTK_MESSAGE_INFO,
//                GTK_BUTTONS_OK, Message );
                GTK_BUTTONS_NONE, Message);
    g_signal_connect( G_OBJECT( dialog ), "response",
                G_CALLBACK( response_cb ), dialog );

    gtk_widget_show( dialog );
    return( TRUE );
    }

int main( int argc, char **argv )
    {
    gtk_init (&argc, &argv);

    g_timeout_add( 2000, (GSourceFunc) timeout_cb, NULL );
    gtk_main();

    return( 0 );
    }

---

Regards,
Alf Stockton    www.stockton.co.za

"Thirty days hath Septober,
April, June, and no wonder.
all the rest have peanut butter
except my father who wears red suspenders."