[gbrainy] Add number logic problem
- From: Jordi Mas <jmas src gnome org>
- To: commits-list gnome org
- Cc:
- Subject: [gbrainy] Add number logic problem
- Date: Sun, 28 Nov 2010 09:47:43 +0000 (UTC)
commit aca141cdfbd4c13233a30d249272e20d16b66e7b
Author: Jordi Mas <jmas softcatala org>
Date: Sun Nov 28 10:49:30 2010 +0100
Add number logic problem
data/games.xml | 31 +++++++++++++++++++++++++++++++
1 files changed, 31 insertions(+), 0 deletions(-)
---
diff --git a/data/games.xml b/data/games.xml
index c9641a7..80d8b23 100644
--- a/data/games.xml
+++ b/data/games.xml
@@ -518,4 +518,35 @@
<_rationale>The variable q is bigger than x and s is bigger than y, if q is bigger than s then the condition x > y is true.</_rationale>
</variant>
</game>
+
+ <game>
+ <_name>Odd number</_name>
+ <type>Logic</type>
+ <difficulty>All</difficulty>
+ <variant>
+ <_question>Given two integer numbers x and y, if x is even and y odd, which of the following expressions gives always an odd result? [option_answers]</_question>
+
+ <string _text = "Possible answers are:" x = "0.1" y = "0.15" size = "large"/>
+
+ <option x = "0.3" y = "0.3" width ="0.45" height ="0.1" order ="randomized" correct = "yes">
+ <string _text = "[option_prefix] 2x + y" x = "0.05" y = "0.02" size = "large"/>
+ </option>
+
+ <option x = "0.3" y = "0.4" width ="0.45" height ="0.1" order ="randomized">
+ <string _text = "[option_prefix] x * y" x = "0.05" y = "0.02" size = "large"/>
+ </option>
+
+ <option x = "0.3" y = "0.5" width ="0.45" height ="0.1" order ="randomized">
+ <string _text = "[option_prefix] x * y * 2" x = "0.05" y = "0.02" size = "large"/>
+ </option>
+
+ <option x = "0.3" y = "0.6" width ="0.45" height ="0.1" order ="randomized">
+ <string _text = "[option_prefix] (x - y) * 2" x = "0.05" y = "0.02" size = "large"/>
+ </option>
+
+ <_rationale>Since x is always an even number, multiplying it by 2 always produces a even number, and adding an even number to an odd number (y) always produces an odd number.</_rationale>
+ </variant>
+
+ </game>
+
</games>
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