Re: [xslt] problem with key and position() function

[Stéphane Mottelet <stephane mottelet utc fr>]

Stéphane Mottelet a écrit :
> Daniel Veillard a écrit :
> > On Mon, Mar 26, 2007 at 03:33:29PM +0200, Stéphane Mottelet wrote:
> >   
> > > Hi folks, I am encoutering a problem when using the
> > > function position() with the result of a key().
> > >     
> > [...]
> >   
> > >             <xsl:value-of select="position(key('match_a','second'))"/>
> > >     
> > [...]
> >   
> > > Is it  a bug, or am I missing something. I would expect to get the result :
> > >
> > > <result>2</result>
> > >     
> >  http://www.w3.org/TR/xslt#function-key
> >  it returns a node-set containing the nodes in the same document as the context node that have a value for the named key equal to this string.
> >
> > there would be only one element in that node set, so the position can only be 1
> > so what you wrote is probably not what you expected.
> >
> >   http://www.w3.org/TR/xpath#function-position
> >
> > does not take any argument.
> > Nothing replace checking the docs a bit when learning a new language
> >
> > Daniel
> >
> >   
> Yes, I am still learning... But do you know a way to do what I am
> expecting ?
>
> S.
I mean something more clever than

   <xsl:template match="doc">
       <result>
           <xsl:for-each select="key('match_a','second')">
               <xsl:value-of select="count(preceding-sibling::*)+1"/>
           </xsl:for-each>
       </result>
   </xsl:template>

S.