Re: [xml] xml find and replace

[stuart shepherd <jonny wark googlemail com>]

Brilliant I've now got this

<?xml version="1.0" encoding="utf-8"?>

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="node()|@*">

  <xsl:copy>

    <xsl:apply-templates select="node()|@*"/>

  </xsl:copy>

 </xsl:template>

<xsl:template match="//control[name='DelaySeconds']/numeric/max/text()">

  <xsl:text>5</xsl:text>

</xsl:template>

<xsl:template match="//control[name='DelaySeconds']/numeric/scalemax/text()">

  <xsl:text>5</xsl:text>

</xsl:template>

</xsl:stylesheet>

And it seems to work, thanks for your help.

On Mon, Jul 16, 2012 at 1:22 PM, Noam Postavsky <npostavs users sourceforge net> wrote:

On Mon, Jul 16, 2012 at 6:09 AM, stuart shepherd
<jonny wark googlemail com> wrote:
> <xsl:template match="//control[name='DelaySeconds']/numeric/max">
> <xsl:element name="{name(.)}">
>         <xsl:value-of select="translate(string(.), '110', '5')" />
> </xsl:element>
> </xsl:template>

I think you could just do

<xsl:template match="//control[name='DelaySeconds']/numeric/max[. =
110]/text()">
  <xsl:text>5</xsl:text>
</xsl:template>

Actually I guess you don't care about the original value so you don't
even need the [. = 110] part.

> I've tried using replace instead of translate but I get the error message
>
> xmlXPathCompOpEval: function replace not found
> XPath error : Unregistered function

replace is an Exslt function, add xmlns:str="http://exslt.org/strings"
to your root node,
then you can call str:replace.