RE: [xml] xmlDocDumpFormatMemory

["Jones, Mark A (Mark)" <jones lucent com>]

below is an exerpt I yanked from the libxml2 documentation.  hope it helps - it suggests to me that the 
function will return the size of the tree in the variable 'size'.


Function:
=========
void    xmlDocDumpFormatMemory  (xmlDocPtr cur, xmlChar ** mem, int * size, int format)

Description:
===========
Dump an XML document in memory and return the #xmlChar * and it's size. It's up to the caller to free the 
memory with xmlFree(). Note that @format = 1 provide node indenting only if xmlIndentTreeOutput = 1 or 
xmlKeepBlanksDefault(0) was called

cur: the document 
mem: OUT: the memory pointer 
size: OUT: the memory length 
format: should formatting spaces been added 


-----Original Message-----
From: xml-bounces gnome org [mailto:xml-bounces gnome org]On Behalf Of
Remy HAREL
Sent: Friday, May 27, 2005 8:12 AM
To: xml gnome org
Subject: [xml] xmlDocDumpFormatMemory


 Re,

  I'm using this function (xmlDocDumpFormatMemory ) to dump my xml tree 
to a xmlChar*, I'm reading the documentation, and I am said it's up to 
me to  specify &size ? how can I know the size of the three that will be 
dumped ? I supposed the memory for the xmlChar** mem will be reserved by 
the function itself ?

 I'm looking for this in the API Doc, but I can't find it.

 Regards,

 Remy

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