Re: [xml] Replacing parts of xml with xsl

From: Daniel Veillard <veillard redhat com>
To: Colin Gillespie <C Gillespie newcastle ac uk>
Cc: xml gnome org
Subject: Re: [xml] Replacing parts of xml with xsl
Date: Fri, 16 Jul 2004 08:17:51 -0400

On Fri, Jul 16, 2004 at 12:06:16PM +0100, Colin Gillespie wrote:

I hopefully have a simple problem.


  Hopefully you have checked the existing examples.

I want to use a xsl style sheet to change a part of the xml that is
specified with an xpath expression.


  XSLT is not defined to work on a subtree.

Any help is appreciated.


  Either make a stylesheet for this or follow the XPath example
    http://xmlsoft.org/examples/index.html#xpath2.c

Daniel

-- 
Daniel Veillard      | Red Hat Desktop team http://redhat.com/
veillard redhat com  | libxml GNOME XML XSLT toolkit  http://xmlsoft.org/
http://veillard.com/ | Rpmfind RPM search engine http://rpmfind.net/

References:
- [xml] Replacing parts of xml with xsl
  - From: Colin Gillespie

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