RE: [xml] Re: how to read the second node?

["Ron Ohmer" <rohmer aisconsulting net>]

That's true...

Actually if you were to do what I stated, you should check the type..


-----Original Message-----
From: xml-admin gnome org [mailto:xml-admin gnome org] On Behalf Of Igor
Zlatkovic
Sent: Wednesday, February 11, 2004 5:21 PM
To: xml gnome org
Subject: [xml] Re: how to read the second node?

shen peng wrote:

> Hello again ,thank you very much ,I solved last problem but the new 
> question is coming out :(
> the format of xml is like this :
> <timetable>
>     <direct_train>
>         <train number = "suX1">
>             .........
>         </train>
>         <train number = "suX2">
>             .........
>         </train>
>     </direct_train>
>     <passing1_train>
>         <train1 number = "subX1">
>             .........
>         </train1>
>     </passing1_train>
> </timetable>
> I can use followed code: doc = xmlParseFile(docname);
>           cur = xmlDocGetRootElement(doc);
>                       cur = cur->xmlChildrenNode;
>          cur = cur->next;//this point to <direct_train>;

No way. If the document is what you have shown, that points to a text 
node that contains whitespace. That node is between <direct_train> and 
<train> and it contains a newline, carriage return perhaps, a few spaces 
and/or perhaps tabs.

> to read the <timetable> as root node ;<direct_train> as its 
> childrennode,but when I finish read the data in <direct_train>,I want to 
> read data in <passing1_train>, do I need go back to the root 
> node"<timetable>", and choose second
> childrennode"<passing1_train>"? how can I do ?

Use XPath to select the nodes you need. Walking the tree is never a good 
idea, unless you analyse an unknown XML structure.

Ciao,
Igor

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