RE: [xml] saving node to a buffer
- From: Roger Reynolds <rogerr softix com>
- To: "'xml gnome org'" <xml gnome org>
- Subject: RE: [xml] saving node to a buffer
- Date: Wed, 14 Apr 2004 17:33:17 +1000
Never mind, I discovered the function xmlNodeDumpOutput
which appears to do what I want.
-----Original Message-----
From: Roger Reynolds [mailto:rogerr softix com]
Sent: Wednesday, April 14, 2004 11:37 AM
To: 'xml gnome org'
Subject: [xml] saving node to a buffer
Given a node in a tree, how does one obtain a string which would represent
the "outer xml" for the node, if you know what I mean?
(by outer xml, I mean an xml element that represents this node and it's
children, contrasted with the "inner xml" which I believe would be
equivalent
to the "content" member of this node, right?)
I started out to use xmlSaveToBuffer to create a save context
to use with xmlSaveTree, however in version 2.6.8 this function,
although documented, is not implemented.
There's got to be a way, right?
Thanks in advance..
roger
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