Re: [xml] a question about getting the element content with name space

[Momena Akter Ahmed <momenaa yahoo com>]

--- Daniel Veillard <veillard redhat com> wrote:
> On Mon, Nov 10, 2003 at 11:35:26PM -0800, Momena
> Akter Ahmed wrote:
> > Here is my xpath :
> > child::node2='test'
> >
> > It worked okay. But after I added the namespace
> stuff,
> > how do I compose my xpath query to compare the
> content
> > of the child node ?
>
>   child::ns:node2='test'
> but you need to have the namespace prefix 'ns'
> defined in the
> XPath context. In XSLT it's inherited from the node
> containing
> the XPath expression. Outside XSLT there is no
> specification defining
> this. The API is 
http://xmlsoft.org/html/libxml-xpathInternals.html#xmlXPathRegisterNs
> to register a namespace to an XPath evaluation
> context.
>
> Daniel

Thanks for the quick response.
My xml looks like this :
<root_node xmlns:pwg="http://www.pwg.org";>
<node1>
  <pwg:node2>test</pwg:node2>
</node1>
</root_node>

The code I am now using is :

xmlXPathRegisterNs (context, (xmlChar *)"pwg",
(xmlChar *)"http://www.pwg.org";);
sprintf (query, "child::pwg:node2='test'"); 

Still it is not working. Using debugger, I can see
that the ns menber of node2 knows about pwg and my
URI.

Momena



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