[xml] XPath namespace filtering...
- From: Sean Chittenden <sean chittenden org>
- To: xml gnome org
- Subject: [xml] XPath namespace filtering...
- Date: Sun, 1 Jun 2003 16:17:28 -0700
I may be confused as to what the XPathContext->namespace struct member
does, but I was under the impression that only nodes whos namespace
was found in XPathContext->namespace would be returned with a given
query. The use case being something akin to:
doc.find('//root_node/foo/bar', 'other_ns').each do |node|
puts "node: #{node.path} #{node.namespaces.join(',')}"
end
And I'd get:
Node path: /root_node/foo/bar[1] namespace: other_ns,rn
Node path: /root_node/foo/bar[3] namespace: other_ns,rn
Node path: /root_node/foo/bar[5] namespace: other_ns,rn
Node path: /root_node/foo/bar[7] namespace: other_ns,rn
Node path: /root_node/foo/bar[9] namespace: other_ns,rn
Instead, when I setup XPathContext->namespace with a namespace with
the other_ns prefix, I'm still get all of the results 1-10. What's
the point of the namespace member? Is there a better way to do an
XPath query for nodes in the other_ns namespace? -sc
--
Sean Chittenden
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