Re: [xml] Ordering of attributes: xmlGetDtdElementDesc()

[Mark S Petrovic <petrovic corp earthlink net>]

On 11Feb, Daniel Veillard wrote:
> On Tue, Feb 11, 2003 at 09:54:34AM -0800, Mark S Petrovic wrote:
> > Given
> >
> > dtdPtr DTD;
> > xmlChar *N;
> > xmlElementPtr E;
> > xmlAttributePtr A;
> >
> >    E = xmlGetDtdElementDesc(DTD,N);
> >    A = E->attributes;
> >
> > is the list of attributes A ordered exactly as those same attributes
> > are ordered in the DTD for the element named N?
>
>   No, because there is no such ordering !

I believe you mean that the ordering is not significant because there
are many logically equivalent representations of an XML document.
Fair enough.  You are therefore free to tell me that further questions
on this have no meaning.

But ---  being a glutton for punishment, the list, in fact has some
order for a given instance of the thing pointed to by dtdPtr DTD.
Is this order something you might comment on?  If not, I understand.

> In general there is no attribute ordering in XML.
> For attribute declarations, some may be done in the internal subset or
> the external subset, and possibly in different ATTLIST declarations in
> both, so basically there is no order in the DTD either.
>
> Daniel
>
> -- 
> Daniel Veillard      | Red Hat Network https://rhn.redhat.com/
> veillard redhat com  | libxml GNOME XML XSLT toolkit  http://xmlsoft.org/
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