Re: [xml] help: how to get content of an element via XPath in lib xml2

[Daniel Veillard <veillard redhat com>]

On Thu, Apr 24, 2003 at 11:40:25AM -0700, andy glew amd com wrote:
> >   You understand that 
> > xmlXPathEvalExpression(document,"/record/field"))
> > returns a node set, that a node set may potentially contain 0, 1 or N 
> > nodes. A nodeset is not a node, you can't xmlGetContent() the result !
>
> I understand the difference between nodesets and nodes.
>
> Actually xmlXPathEvalExpression
> returns an xmlXPathObjectPtr.
> I am having trouble figuring out
> how that maps into a xmlNodeSetPtr.

  Read the data definitions, they are public !

  if (obj->type == XPATH_NODESET) {
       xmlNodeSetPtr nodes;

       nodes = obj->nodesetval;
       if ((nodes != NULL) && (nodes->nodeTab != NULL)) {
           int i;

           for (i = 0;i < nodes->nodeNr;i++) {
               handle(nodes->nodeTab[i]);
           }
       }
  }

Daniel

-- 
Daniel Veillard      | Red Hat Network https://rhn.redhat.com/
veillard redhat com  | libxml GNOME XML XSLT toolkit  http://xmlsoft.org/
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