RE: [xml] external dtd insertion

["Henke, Markus" <Markus_Henke ordat com>]

Hello Deryk,

If i got it right, the reference to an external subset is
equivalent to the root node of an internal subset
(so to say).
Therefore, try to use

  xmlCreateIntSubset(doc, "foo", NULL, "./foo.dtd");

That works for me, i hope it'll also for you.


Ciao, Markus



> -----Original Message-----
> From: Deryk Robosson [mailto:deryk www iitowns com]
> Sent: Saturday, April 06, 2002 11:37 AM
> To: xml gnome org
> Subject: [xml] external dtd insertion
>
>
> I am unable to figure out exactly what I need in regards to adding an
> existing doctype declaration to a document created on the fly.
>
> What I've tried thus far is:
>
> xmlDocPtr doc;
> xmlDtdPtr dtd;
>
> doc = xmlNewDoc("1.0");
> dtd = xmlNewDtd(doc, "foo", "SYSTEM", "./foo.dtd");
> doc->children = xmlNewDocNode(doc, NULL, "test", NULL);
> xmlDocDump(stderr, doc);
>
> The above does not insert the <!DOCTYPE> line into the doc 
> dump output.
> The following does not as well:
>
> xmlDocPtr doc;
>
> doc = xmlNewDoc("1.0");
> doc->exSubset = xmlNewDtd(doc, "foo", "SYSTEM", "./foo.dtd");
> doc->children = xmlNewDocNode(doc, NULL, "test", NULL);
> xmlDocDump(stderr, doc);
>
>
> Any advice or pointers to a page on the site I perhaps misses is
> appreciated.