Re: Getting indexes of row's children in treeview

[Phil Wolff <adiabat centurylink net>]

If I'm reading your question correctly, you're looking for path.up() and 
path.down() to change levels in the tree, and path.next() and 
path.prev() to change nodes within a level. Continuing your example and 
assuming iter points to row 3,

    cout << path.to_string() << endl; // 3
    path.down();
    cout << path.to_string() << endl; // 3:0
    path.next();
    cout << path.to_string() << endl; // 3:1
    path.down();
    cout << path.to_string() << endl; // 3:1:0
    ...

On 2016/06/28 09:22, Kamalpreet Grewal wrote:
> Hi
>
> I have been trying to get the index value of rows in a treeview. I did it using:
>
> path = _tree.get_model()->get_path(iter);
> int i = atoi(path.to_string().c_str());
>
> This works well by storing selected row's index in 'i'. Next I have
> children in these rows and I wish to get the index of the child of a
> row selected.
>
> And I came across: http://scentric.net/tutorial/sec-treemodel-rowref.html
> How the indexes are assigned at different depths in a treeview is
> well-explained at this link in the beginning only.
>
> Obtaining these indexes in the form "0:1" etc has been an issue for
> me. How can this be done? Are there any alternatives to get indexes of
> children of rows?
>
> Thanks in advance.