Re: Help
- From: Paul Barton-Davis <pbd Op Net>
- To: "Florent. Devin" <Florent Devin lifl fr>
- Cc: Rasoul Hajikhani <rhajikhani exchange office etoys com>, gtk-list gnome org
- Subject: Re: Help
- Date: Wed, 22 Nov 2000 07:02:49 -0500
>> Can any one tell me how to show a widget after a timer runs out but not at
>> the execution of the application?
>> -r
>If I understand you
>Try to do
>while (gtk_events_pending())
> gtk_main_iteration
i don't think that this is what he meant. i think he wants:
1) program starts
2) gtk_init()
3) creates some widgets
4) show()'s most of the widgets
5) gtk_run()
.
.
. <some number of seconds>
6) show() some other widgets
the answer is to do this between steps 4 and 5:
gtk_timeout_add (msecs, function, argument);
and within `function':
gint function (void *arg)
{
other_widget1->show ();
other_widget2->show ();
return FALSE; /* don't execute this function again */
}
--p
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