Re: Help

[Rasoul Hajikhani <rhajikhani exchange office etoys com>]

Actually, this is what I mean:
  1) program starts
  2) gtk_init()
  3) creates some widgets
  4) show() all of the widgets created
  5) gtk_run()
  .  
  .
  .  <some number of seconds>
  6) create another widget (which has other widgets in it)
  7) show() the other widget


On Wed, 22 Nov 2000, Paul Barton-Davis wrote:

> >> Can any one tell me how to show a widget after a timer runs out but not at
> >> the execution of the application?
> >> -r
> >If I understand you 
> >Try to do 
> >while (gtk_events_pending())
> >  gtk_main_iteration
> 
> i don't think that this is what he meant. i think he wants:
> 
>   1) program starts
>   2) gtk_init()
>   3) creates some widgets
>   4) show()'s most of the widgets
>   5) gtk_run()
>   .  
>   .
>   .  <some number of seconds>
>   6) show() some other widgets
> 
> the answer is to do this between steps 4 and 5:
> 
>     gtk_timeout_add (msecs, function, argument);
> 
> and within `function':
> 
>     gint function (void *arg)
>     {
>          other_widget1->show ();
> 	 other_widget2->show ();
> 
> 	 return FALSE; /* don't execute this function again */
>     }
>     
> --p  
> 
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