Re: Complex Calculations




On Tue, 2008-02-26 at 06:10 +1100, John Machin wrote:
Ralph Shumaker wrote:
John Machin wrote:
Secondly, you don't need sum(En-Fn) ... just En-Fn is enough.
  

En-Fn will give you the difference.  sum(En-Fn) is different. 

Where x is a scalar, how can sum(x) differ from x?

Give
=sum("a")="a"
a try

:-)

Andreas





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