[xslt] HTML DOCTYPE added in a XML string after applying a style sheet
- From: "Charles G." <carlito g free fr>
- To: xslt gnome org
- Subject: [xslt] HTML DOCTYPE added in a XML string after applying a style sheet
- Date: Thu, 27 Jun 2013 11:11:56 +0200 (CEST)
Hi Everybody !
I'm a newbie with XSLT and I need some help.
Here is my problem:
My inputs:
-a string with a xml tree.
-a stylesheet file
My output:
- another XML string
I obtain what I want in the output except for one thing, when the stylesheet is applied XSLT add:
<!DOCTYPE html PUBLIC \"-//W3C//DTD HTML 4.0 Transitional//EN\" \"http://www.w3.org/TR/REC-html40/loose.dtd\">
in my result string and I don't want this.
This is strange as it is not a HTML doc.
Here is my code (according to the tutorial here http://xmlsoft.org/XSLT/tutorial/libxslttutorial.html):
xmlSubstituteEntitiesDefault(1);
xmlLoadExtDtdDefaultValue = 1;
...
m_xslt = xsltParseStylesheetFile((const xmlChar *)xsltFilePath);
m_inputXmlDoc = xmlParseMemory(input, size);
m_outputXmlDoc = xsltApplyStylesheet(m_xslt, m_inputXmlDoc, NULL);
at this point when I check outputXmlDoc, I can see
outputXmlDoc->type == XML_HTML_DOCUMENT_NODE
outputXmlDoc->children->type = XML_DTD_NODE
I tried
xmlLoadExtDtdDefaultValue = 0;
I 've searched in the archive list and in google but so far, I just read that the DTD cannot be turned off
... but maybe I
am missing something ...
Is there a way to specify xsltApplyStylesheet for not including the DTD node ? Maybe through params ?
Thank you for your help.
Charles
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