'Re: "Re: [xslt] XPath expression question"'

[Kasimier Buchcik <kbuchcik 4commerce de>]

Hi,

on 4/14/2004 11:07 AM Bernhard Zwischenbrugger wrote:

> Hi Vladimir
> 
> Try this:
> 
> 
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
> <xsl:template match="/">
>   <result>
>       <xsl:copy-of select="/mixed/*|/mixed/text()"/>
>   </result>
> </xsl:template>
> 
> </xsl:stylesheet>
> 
> Bernhard

You may want to use the following as well:

<xsl:copy-of select="/mixed/child::node()"/>

It selects all child nodes, regardless which type.

>>Please help
>>How I can make copy-of for all children of current node, including text
>>blocks ?
>>
>>My example:
>>
>><mixed>
>>   <subnode1/>
>>   text
>>   <subnode2>
>>	sub-text
>>   </subnode2>
>>   another text
>></mixed>
>>
>>with XSLT  transformation:
>>
>><xsl:template match="/">
>>  <result>
>>    <xsl:copy-of select="/mixed/*"/>
>>  </result>
>></xsl:template>
>>
>>I will get only sub-nodes of mixed, but How I can get all contents
>>including text blocks ?
>>
>>I get:
>><result>
>>   <subnode1/>
>>   <subnode2>
>>	sub-text
>>   </subnode2>
>></result>
>>
>>I need:
>><result>
>>   <subnode1/>
>>   text
>>   <subnode2>
>>	sub-text
>>   </subnode2>
>>   another text
>></result>


Kasimier