Re: [xml] Dump document to a buffer without xml version



On Wed, Aug 20, 2014 at 07:04:06PM +0200, Iñigo Martínez wrote:
Hi:

I'm working with a protocol based on XML, something like:

<Command Timestamp="0" ReceptionTimeStamp="0" Sender="P1"
Receiver="P2"><GetData/></Command>

I can successfully parse these messages using xmlReadMemory and
navigating through the tree. When trying to create my own messages I
can create them successfully this way:

doc = xmlNewDoc(NULL);
node = xmlNewNode(NULL, BAD_CAST "Command");
xmlDocSetRootElement(doc, node);

xmlNewProp(node, BAD_CAST "Timestamp", BAD_CAST "0");
xmlNewProp(node, BAD_CAST "ReceptionTimestamp", BAD_CAST "0");
xmlNewProp(node, BAD_CAST "Sender", BAD_CAST "P1");
xmlNewProp(node, BAD_CAST "Receiver", BAD_CAST "P2");

xmlNewChild(node, NULL, BAD_CAST "GetData", NULL);

The problem comes when trying to get the correspondant string as I get
the xml version in the output:

<?xml version="1.0"?><Command Timestamp="0" ReceptionTimeStamp="0"
Sender="P1" Receiver="P2"><GetData/></Command>

I have seen some tricks using a xmlTextWriter, but in my case I need
an string not a file.

Is there any way to avoid it ?

  Best way is to use the 'new' saving APIs

http://xmlsoft.org/html/libxml-xmlsave.html#xmlSaveToBuffer
with XML_SAVE_NO_DECL in the option

and use
http://xmlsoft.org/html/libxml-xmlsave.html#xmlSaveDoc

if you are piling up such messages on an IO just use anothe xmlSaveTo...
function and Flush to output instead of writing in memory and doing
the I/O separately

Daniel

-- 
Daniel Veillard      | Open Source and Standards, Red Hat
veillard redhat com  | libxml Gnome XML XSLT toolkit  http://xmlsoft.org/
http://veillard.com/ | virtualization library  http://libvirt.org/


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