Re: [xml] xsltApplystylesheet fails when Xpath functions are use in xsl

["Buchcik, Kasimier" <k buchcik 4commerce de>]

Hi,

> -----Original Message-----
> From: xml-bounces gnome org [mailto:xml-bounces gnome org] On 

> I have following code
>
> int main()
> {
>
>     xmlDocPtr doc = xmlParseFile("xmlfile.xml");
>     xsltStylesheetPtr xsl=xsltParseStylesheetFile("xslfile.xsl");
>     xmlDocPtr result = xsltApplyStylesheet(xsl, doc, NULL);
>
>     xmlSaveFile("stylesheet_output.xml", result);
>
>     xmlFreeDoc(doc);
>     xmlFreeDoc(result);
>     xsltFreeStylesheet(xsl);
>     return 0;
> }
>
> The program work fine when my xsl do not use any of the XPath 
> functions. I have a use case where I need  to replace all the 
> single quotes with double single quotes. To achive this i 
> wrote a xsl where i used XPath "replace" function. the 
> program fails giving following output
>
> xmlXPathCompOpEval: function replace not found
> XPath error Unregistered function in replace($VAR1, $QUOTE, $DQUOTE)
> xmlXPathCompiledEval: 2 object left on the stack
> runtime error: file xslfile.xsl element value-of
>
> the same xml when opened in browser gives me correct output.
>
> I also tried using xsltproc this too gives the same error as 
> shown above.
>
> Can some one tell me the reason for this behavior.

You may want to use the EXSLT function "replace", since there
is no XPath or XSLT 1.0 function with that name.

See http://www.exslt.org/str/functions/replace/index.html

Register the EXSLT function for Libxslt with exsltRegisterAll().

Regards,

Kasimier