Re: [xml] Smart way to get ancestors?

["Michael Ransburg" <michael ransburg itec uni-klu ac at>]

Hi!

A small update, this is the way I retrieve the ancestors now:

        node = xmlTextReaderExpand(reader);

        node->children = NULL;
        node->prev = NULL;
        node->next = NULL;

        while (node->parent != NULL) {
                node = node->parent;
        }
        xmlDocSetRootElement(doc,xmlCopyNode(node->children,1));

This works fine - is it a proper way to accomplish this?

Thanks,
Michael


-- 
Michael Ransburg, Dipl.-Ing.
Project Assistant, PhD Candidate
Department of Information Technology (ITEC)
Klagenfurt University / Austria
http://www.ifi.uni-klu.ac.at/ITEC/Staff/Michael.Ransburg
 


> _____________________________________________ 
> From:         xml-bounces gnome org [mailto:xml-bounces gnome org]  On
> Behalf Of Michael Ransburg
> Sent: Friday, July 07, 2006 8:12 PM
> To:   xml gnome org
> Subject:      [xml] Smart way to get ancestors?
>
> Hi!
>
> I'm using the XMLTextReader to parse a document, for example:
>
> <A>
>       <B/>
>       <C/>
>       <D>
>               <E/>
>               <F>
>                       <G/>
>               </F>
>       </D>
> </A>
>
> Now lets say that I reach the node <G> and would like to copy its
> ancestors (<A>, <D>, <F>) to a new document. The way I'm currently doing
> it is to use some temporary nodes and a lot of "xmlCopyNode(node,2)" in
> order to get rid of unwanted siblings. Is there a nicer way to get the
> ancestors of a given node as a new document?
>
> Thanks,
> Michael
>
>
>  << File: ATT00007.txt >>

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