Re: [xml] xpathEval and namespaces

[Martijn Faassen <faassen infrae com>]

Daniel Veillard wrote:
> On Tue, Sep 14, 2004 at 12:47:43PM +0200, Jos Vos wrote:
>
> > With this even docroot.xpathEval('/head') gives an empty nodeset back
> > (docroot is my root node object), while it works fine when I remove
> > the namespace attributes.
>
>
>   that's normal /foo does not select namespaced nodes, it's the XPath spec.
> It's probably #1 FAQ for XPath. As explained dozens of time you must 
> bin a prefix to that namespace in the XPath context and use the prefix in
> the query. I don't remember if/how it's doable from Python.

Sure:

context = dom.xpathNewContext()
...
context.xpathRegisterNs(prefix, uri)

Now Daniel has time to look into my namespace-related bug report. :)

Regards,

Martijn