Re: [xml] followup on inserting dtd

[Daniel Veillard <veillard redhat com>]

On Sun, Apr 07, 2002 at 03:26:54PM +0800, Deryk Robosson wrote:
> Okay, I managed to find the thread:
>
> http://mail.gnome.org/archives/xml/2002-January/msg00226.html
>
> The search facility is rather useless..manually skimming the subjects was
> the key.  However, the final entry of that thread is exactly the state
> that I am in also.  Doing it the way Daniel suggests as:
>
>   doc = xmlNewDoc("1.0");
>   dtd = (xmlDtdPtr) xmlParseDTD("netlogon",
> "/home/deryk/netlogon/netlogon.dtd");
>
>   /* here to ... are Daniels suggested methods */
>   doc->intSubset = dtd;
>
>   if(doc->children == NULL)
>     xmlAddChild((xmlNodePtr)doc, (xmlNodePtr)dtd);
>   else
>     xmlAddPrevSibling(doc->children, (xmlNodePtr)dtd);
>   ...
>   xmlDocDump(stderr, doc);

  Looks correct,

> Still does not insert the external doctype reference into the document as
> one would expect.  The document itself is generated fine no problems.

  Damn, well there is only One True Way: take a debugger, put a breakpoint
in xmlDocDump and see what happens. I could do this, but you are in a better
situation to do it, isn't it ?

> Given the nature of the library and the document formats in general one
> would presume that it would indeed be as simple as adding another node to
> the list as all the snippets I've seen would suggest. :)

  Well DTDs are a bit more complex in the sense that they aren't part
part of the document tree as usual, they are not XML themselves.

Daniel

-- 
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