Forcing menus position
- From: Mario Domenech Goulart <mario inf ufrgs br>
- To: sawfish-list gnome org
- Subject: Forcing menus position
- Date: Sun, 27 Nov 2005 12:50:32 +0000
Hello
Is there a "non-intrusive" way to force a position for menus to be
displayed? For example, I want some of my menus to be displayed always
at the bottom-left corner of the screen, no matter the position of the
cursor.
I could get this by modifying the `popup-menu' function from the
menus.jl file (diff output at the end of the message).
So, I can do something like
(popup-menu my-menu (cons 0 (screen-height)))
to place `my-menu' at the bottom-left corner of the screen.
Is there a non-intrusive way of doing this? If there is not, John, can
you consider applying the modifications to menus.jl?
Best wishes.
Mario
$ diff -u ~/menus.jl lisp/sawfish/wm/menus.jl
--- lisp/sawfish/wm/menus.jl 2005-11-27 12:38:09.000000000 +0000
+++ /home/mario/menus.jl 2005-11-27 12:24:09.000000000 +0000
@@ -262,7 +262,7 @@
(user-eval result))
(t result)))))
- (define (popup-menu spec)
+ (define (popup-menu spec #!optional position)
(or spec (error "No menu given to popup-menu"))
(if (and menu-active menu-process (process-in-use-p menu-process))
(error "Menu already active")
@@ -297,7 +297,7 @@
(rplacd offset
(max 0 (+ (cdr offset) (cdr dims)
(cdr (window-position menu-active))))))
- (setq offset nil))
+ (setq offset position))
(setq nickname-table (make-table eq-hash eq))
(setq nickname-index 0)
(format menu-process "(popup-menu %s %S %S)\n"
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