handling exception without stderr printings

[Pablo Madoery <madoerypablo gmail com>]

Hello. 

I have the following code:

#include <libxml++/libxml++.h>

#include <iostream>

#include <stdlib.h>

using namespace std;

using namespace xmlpp;

int main()

{

try

{

xmlpp::DomParser parser;

parser.set_throw_messages(true);

parser.parse_file("config.xml");

}

catch (const xmlpp::exception& ex)

{

cout << ex.what() << endl;

}

return 0;

}

The problem i have is the following:

In the case that "config.xml" doesn't exist I want that only exception cout be printed (and not stderr).

But that's not the case. The exception is raised and the stderr is printed too.

How can i make that stderr dont be printed.

Can you help me?.

Thank you very much.