Re: [gtkmm] comparing Glib::ustring's ...

["Jeffrey S. Gavin" <jeff ezclick net>]

Hmmm,

I don't see this. 

From this:

   cout << "\"AAA\" < \"aaa\" --> " << (("AAA" < "aaa") ? "true" : 
"false") << endl;
  
   Glib::ustring A = "AAA";
   Glib::ustring a = "aaa";
  
   cout << "A < a --> " << ((A < a) ? "true" : "false") << endl;
  
   Glib::ustring test1="AAA",test2="aaa";
  
   std::cout << (test1<test2) << std::endl;
   std::cout << (test1>test2) << std::endl;
   std::cout << (test1==test2) << std::endl;

I get:

"AAA" < "aaa" --> true
A < a --> true
1
0
0

What is the output of your program when you run it?

Jeff

bart wrote:

> Hi,
>
> When sorting some Glib::ustring's in a list, i encountered a strange
> problem. If i compare "AAA" to "aaa", i expect "AAA" to be
> alphabetically first. But according to the overloaded '<', "aaa" is
> first :S
>
> I have always learned uppercase comes first and other STL sorting
> methods seem to honor this. ( e.g. sort )
>
> I am quite pissed off by this behaviour and hope someone can shed some
> ligth on this. Attached to this message is a scrap of code which
> illustrates my problem.
>
> TIA,
>
> Bart
>
> ----------------------------------------------------
> #include <iostream>
> #include <glibmm/ustring.h>
>
> int main()
> {	
> 	Glib::ustring test1="AAA",test2="aaa";
> 	
> 	std::cout << (test1<test2) << std::endl;
> 	std::cout << (test1>test2) << std::endl;
> 	std::cout << (test1==test2) << std::endl;
>
> 	return 0;
> }
>
>
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