Re: How to get the widget's size before it has been shown?
- From: G Hasse <gorhas raditex se>
- To: Lazy Fox <lazy fox wu gmail com>
- Cc: gtk-app-devel-list gnome org, gtk-list gnome org
- Subject: Re: How to get the widget's size before it has been shown?
- Date: Wed, 3 Sep 2008 13:39:18 +0200
On Wed, Sep 03, 2008 at 06:30:25PM +0800, Lazy Fox wrote:
/* How to get the widget's size before it has been shown?
*
* There are two "printf" statements below. I want to get the widget's
size at the first printf.
* How to do this?
*/
#include <gtk/gtk.h>
int main( int argc, char *argv[] )
{
GtkWidget *window;
gtk_init (&argc, &argv);
window = gtk_window_new (GTK_WINDOW_TOPLEVEL);
printf("width=%d \n", window->allocation.width); // return 1
gtk_widget_show (window);
printf("width=%d \n", window->allocation.width); // return 200
gtk_main ();
return 0;
}
You can't do that. Depending on how widgets are packed together
the size must be calculated. That is just what gtk_widget_show
does. You can eaven change packeting in runtime. Then you must
make a new expose, where the size should be recalculated.
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Göran Hasse
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