Re: A Question about GtkTreeSortable

[Christian Neumair <chris gnome-de org>]

Am Donnerstag, den 20.10.2005, 17:44 +0200 schrieb Iago Rubio:
> On Thu, 2005-10-20 at 19:06 +0800, searun wrote:
> > Hi ,
> >
> > Now i want to use GtkTreeSortable to sort a list. The first entry in the
> > gtk_tree_view is an information entry which needn't to be sorted, so i don't
> > want the GtkTreeIterCompareFunc function use the first entry. In my programe
> > i check GtkTreeIter, if it is the same as the first iter, the
> > GtkTreeIterCompareFunc will return 0.
>
> How are you comparing those iters ?
>
> > BUT it can't work. After two day's debug, i can't find the reason.
> >
> > Any help is appreciated, even if you have another good method.
>
> Try to compare the paths with gtk_tree_path_compare() instead of
> comparing the iters. I don't know a generic function to compare iters.
>
> gint       
> your_tree_iter_compare_func  (GtkTreeModel *model,
>                               GtkTreeIter *a,
>                               GtkTreeIter *b,
>                               gpointer user_data)
> {
> GtkTreePath* path_first;
> GtkTreePath* path_a;
> GtkTreePath* path_b;
>
> first_path = gtk_tree_path_new_first();
> path_a = gtk_tree_model_get_path (model,a);
> path_b = gtk_tree_model_get_path (model,b);
>
> if( gtk_tree_path_compare(path_first, path_a) == 0 ){
>       return -1; // "a" is first so "a" always sorts before
> }else if ( gtk_tree_path_compare(path_first, path_b) == 0 ){
>       return 1;  // "b" is first so "a" always sorts after
> }
>
> // none of both are first so compare them 
>
> .....
>
> gtk_tree_path_free(path_first);
> gtk_tree_path_free(path_a);
> gtk_tree_path_free(path_b);
> }

Note that this will IMHO only work if the informal row is inserted into
the model before any other row.

-- 
Christian Neumair <chris gnome-de org>