Re: gui in fonction
- From: TORRI Vincent <Vincent Torri math u-bordeaux fr>
- To: Axel <axel azerty netcourrier com>
- Cc: gtk-app-devel-list gnome org
- Subject: Re: gui in fonction
- Date: Tue, 18 Mar 2003 11:47:25 +0100 (CET)
On Tue, 18 Mar 2003, Axel wrote:
hi
I have a problem with fonction.
basically, i d like to use fonction to build my gui, so here is the function I d like to use
void create_window(GtkWidget *window)
{
window=gtk_window_new (GTK_WINDOW_TOPLEVEL);
gtk_widget_set_size_request(GTK_WIDGET(window),500,250);
}
I call it in main() as following :
GtkWidget *window;
create_window(window);
gtk_widget_show(window);
the problem is that my program segfault.
No problem when I use gtk_window_new et set_size in the main().
So is it possible to build a gui in an external function ? Where is my error ?
Hello,
One solution could be :
GtkWidget *create_window()
{
GtkWidget *window;
window=gtk_window_new (GTK_WINDOW_TOPLEVEL);
gtk_widget_set_size_request(GTK_WIDGET(window),500,250);
return window;
}
and in your main :
GtkWidget *window;
window = create_window();
gtk_widget_show(window);
regards
Vincent TORRI
Thanks in advance
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--
TORRI Vincent
Mathematiques Appliquees Bordeaux
Institut de Mathematiques
Universite Bordeaux 1
351 cours de la liberation
33 405 Talence cedex - France
Tel : 33 (0)5 57 96 21 42
Fax : 33 (0)5 56 84 26 26
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