Re: Question about Timeouts

[<learfox furry ao net>]

> I have not quite figured this one out. I have a callback that shows a
> pop_up menu that displays a series of pixmaps. It looks something like
> this:
>
>     banner_window = create_banner_window ();
>
>    timeout_id = gtk_timeout_add(1500.0, timout_callback, banner_window);
>
>    gtk_widget_show(banner_window);
>    gtk_window_reposition(GTK_WINDOW(banner_window), x_pos, y_pos);
>
>    while(gtk_events_pending())
>    {
>       gtk_main_iteration();
>    }
>
> //---- callback continues
>
> My question is: Will the timeout function get called if the timer period
> expires while still inside the callback? or does the timer only run
> while gtk is in the gtk_main function?

> From my experiance, the timeouts are called under two conditions,
when gtk_main_iteration() is called or when controlling returns to
the level of the highest gtk_main() and when the time interval has been
reached in both cases.

The timeout won't be called `async' when one of your functions is in
execution unless your function has a gtk_main_itteration() or a
gtk_main() in it.


> I ask this because this pixmaps should display while the processes in
> the callback are being run but it onlly seems to get run after the
> callback exits.

Was there a callback placed in your example? It looks like the callbacks
are called *after* your gtk_events_pending() loop.

I think you need to put a gtk_main_iteration() inside yer callback
functions.


--
Sincerely,                  ,"-_                         \|/
-Capt. Taura M.             ,   O=__                    --X--
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                  http://furry.ao.net/~learfox/