Re: [gedit-list] Fwd: =0A=

[Doug McNutt <douglist macnauchtan com>]

At 17:32 +0100 3/11/13, Adam wrote:
> On 10.03.2013 23:32, Doug McNutt wrote:
> > At 19:10 +0100 3/10/13, Adam wrote:
> > > I have recevied a c code.
> > > Every line has a =0A=at the end of the line.
> > >
> > > Does it mean that it is windows EOF char ?
> > > What is the best way to remove it ?
> >
> > At 18:32 -0300 3/10/13, Matheus Boy wrote:
> >
> > > 0x0A is ASCII for LF, Line Feed, '\n'.
> > > My piece of advice: don't remove those chars, try changing the encoding of the file.
> > > BTW, EOF in ASCII is 0x04.
> > >
> > > 2013/3/10 Adam <<mailto:adammaj1 o2 pl>adammaj1 o2 pl>
> >
> >
> > The =0A item looks a lot like "quoted printable" as a feature of email special encoding for otherwise 
> > unrecognized binary items that are not printable in the current user's machine.
> >
> > Of course we, and likely you, don't know the sender's machine's OS.
> >
> > You probably need to decode the data and gedit isn't very good at that. If the file opens without gedit 
> > complaining the "line" probably ends with =0A\n but it might be =0A\r\n with gedit accepting the official 
> > internet linend character pair \r\n.
> >
> > hexdump or just hd piped to gedit using Terminal.app would show the facts.
> >
> > hd PathToTheFile | gedit
> >
> > You can probably just delete the ASCII character string "=0A" with gedit's search and replace but do try it 
> > with a copy.
> >
> > You might be able to recover by substituting ";\n" for every semicolon if it's really a simple source code 
> > in C.
> Thx.
>
> Here is a fragment of file ( maybe it will help ):
>
> /* by ........ 2005=0A=
>   all parts of this program are under the GNU GPL */=0A=
> =0A=
> #include <stdio.h>=0A=
> #include <stdlib.h>=0A=
> #include <math.h>=0A=
> #include <float.h>=0A=
> =0A=
> #include "complex.h"=0A=
> #include "zero.h"=0A=
> =0A=
> =0A=
>
> another part with ; :
>
>
> =0A=
>    dz =3D c_div (y, y1);=0A=
> =0A=
>
> I have tried hd :
>
>
> 00000020  20 20 61 6c 6c 20 70 61  72 74 73 20 6f 66 20 74  |  all parts of t|
> 00000030  68 69 73 20 70 72 6f 67  72 61 6d 20 61 72 65 20  |his program are |
> 00000040  75 6e 64 65 72 20 74 68  65 20 47 4e 55 20 47 50  |under the GNU GP|
> 00000050  4c 20 2a 2f 3d 30 41 3d  0d 0a 3d 30 41 3d 0d 0a  |L */=0A=..=0A=..|
> 00000060  23 69 6e 63 6c 75 64 65  20 3c 73 74 64 69 6f 2e  |#include <stdio.|
> 00000070  68 3e 3d 30 41 3d 0d 0a  23 69 6e 63 6c 75 64 65 |h>=0A=..#include|
> 00000080  20 3c 73 74 64 6c 69 62  2e 68 3e 3d 30 41 3d 0d  | <stdlib.h>=0A=.|

The =3D proves the quoted printable analysis.   3D is the ASCII = sign which is used to introduce the pairs 
of hex digits that allow for transmission of ASCII characters that are not printable - meaning that they 
don't have a grapheme associated with them in a font. Because the = sigh has special meaning it has to be 
encoded as if it were unprintable.

Have a look here.
<http://www.webatic.com/run/convert/qp.php>
  I just pasted your last few lines in and received:


*****Begin copy ***
/* by ........ 2005
   all parts of this program are under the GNU GPL */

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <float.h>

#include "complex.h"
#include "zero.h"



another part with ; :


    dz = c_div (y, y1);

***end copy***

My guess is that you could just remove all "=0A" triplets followed by changing =3D to just = and then 
removing all = signs that appear at an end of a line.  Another place you might look is:
<en.wikipedia.org/wiki/Quoted-printable>
-- 

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