[gvfs] fuse: Round up the number of blocks that a filesystem has

[Ross Lagerwall <rossl src gnome org>]

commit af1e2dd22047e1f95c245a9ada11958899f20278
Author: Ross Lagerwall <rosslagerwall gmail com>
Date:   Mon Nov 11 19:11:49 2013 +0200

    fuse: Round up the number of blocks that a filesystem has
    
    If a filesystem is 4095 bytes, indicate that it uses 1 block rather than
    0 blocks.
    
    https://bugzilla.gnome.org/show_bug.cgi?id=711855

 client/gvfsfusedaemon.c |    2 +-
 1 files changed, 1 insertions(+), 1 deletions(-)
---
diff --git a/client/gvfsfusedaemon.c b/client/gvfsfusedaemon.c
index e2a59b0..11fc1d0 100644
--- a/client/gvfsfusedaemon.c
+++ b/client/gvfsfusedaemon.c
@@ -654,7 +654,7 @@ vfs_statfs (const gchar *path, struct statvfs *stbuf)
       if (file_info)
         {
           if (g_file_info_has_attribute (file_info, G_FILE_ATTRIBUTE_FILESYSTEM_SIZE))
-            stbuf->f_blocks = g_file_info_get_attribute_uint64 (file_info, G_FILE_ATTRIBUTE_FILESYSTEM_SIZE) 
/ 4096;
+            stbuf->f_blocks = (g_file_info_get_attribute_uint64 (file_info, 
G_FILE_ATTRIBUTE_FILESYSTEM_SIZE) + 4096 - 1) / 4096;
           if (g_file_info_has_attribute (file_info, G_FILE_ATTRIBUTE_FILESYSTEM_FREE))
             stbuf->f_bfree = stbuf->f_bavail = g_file_info_get_attribute_uint64 (file_info, 
G_FILE_ATTRIBUTE_FILESYSTEM_FREE) / 4096;