[gnome-shell] popupMenu: Treat a menu will all invisible menu items as empty

[Jasper St. Pierre <jstpierre src gnome org>]

commit 30179bb60d9788faa04a2fb9703f15429da9727d
Author: Jasper St. Pierre <jstpierre mecheye net>
Date:   Thu Feb 14 16:48:28 2013 -0500

    popupMenu: Treat a menu will all invisible menu items as empty
    
    As an example, a menu that has only settings actions might
    be "empty" if allowSettings is false.
    
    https://bugzilla.gnome.org/show_bug.cgi?id=681540

 js/ui/popupMenu.js |    6 +++++-
 1 files changed, 5 insertions(+), 1 deletions(-)
---
diff --git a/js/ui/popupMenu.js b/js/ui/popupMenu.js
index 9807b62..5123696 100644
--- a/js/ui/popupMenu.js
+++ b/js/ui/popupMenu.js
@@ -914,7 +914,11 @@ const PopupMenuBase = new Lang.Class({
     },
 
     isEmpty: function() {
-        return this.box.get_n_children() == 0;
+        let hasVisibleChildren = this.box.get_children().some(function(child) {
+            return child.visible;
+        });
+
+        return !hasVisibleChildren;
     },
 
     isChildMenu: function(menu) {