[gbrainy] Fixes bugzilla #663259

[Jordi Mas <jmas src gnome org>]

commit b6c77d3a95ab4bb7f6ca99adc07938b115e8157f
Author: Jordi Mas <jmas softcatala org>
Date:   Fri Nov 4 18:06:53 2011 +0100

    Fixes bugzilla #663259

 src/Games/Logic/PuzzleTrains.cs |    6 +++---
 1 files changed, 3 insertions(+), 3 deletions(-)
---
diff --git a/src/Games/Logic/PuzzleTrains.cs b/src/Games/Logic/PuzzleTrains.cs
index 0e9a539..c07a84a 100644
--- a/src/Games/Logic/PuzzleTrains.cs
+++ b/src/Games/Logic/PuzzleTrains.cs
@@ -78,10 +78,10 @@ namespace gbrainy.Games.Logic
 					// Translators:
 					//  - mph (miles per hour). You must localize this using the right unit of speed for your locale
 					// - The translated string should not use more characters than the original sentence
-					translations.GetPluralString ("A train leaves the station traveling at {0} mph. {1} hour later a second train leaves the station traveling in the same direction at {2} mph. How many hours since the first train left does it take the second train to overtake the first train?",
-						"A train leaves the station traveling at {0} mph. {1} hours later a second train leaves the station traveling in the same direction at {2} mph. How many hours since the first train left does it take the second train to overtake the first train?", (int) hours),
+					translations.GetPluralString ("A train leaves the station traveling at {0} mph. {1} hour later a second train leaves the station traveling in the same direction at {2} mph. How many hours does it take the second train, since it starts moving, to overtake the first train?",
+						"A train leaves the station traveling at {0} mph. {1} hours later a second train leaves the station traveling in the same direction at {2} mph. How many hours does it take the second train, since it starts moving, to overtake the first train?", (int) hours),
 						speed_a, hours, speed_b);
-			
+
 				answer = translations.GetString ("You can calculate the answer by multiplying the speed of the first train by the time and dividing it by the difference of speeds.");
 				break;
 			}