Re: [g-a-devel] a11y bus trouble after upgrade



On Wed, Apr 23, 2014 at 09:16:28AM +0100, Patrick Welche wrote:
On Sat, Apr 19, 2014 at 05:52:53PM +0100, Patrick Welche wrote:
I have been upgrading eg dbus, glib, at-spi2-core etc. and now registryd
won't start. The best test so far, which is I think what
get_accessibility_bus_address_dbus() does in at-spi2-core atspi-misc.c is:

  dbus-send --print-reply --dest=org.a11y.Bus /org/a11y/bus \
  org.a11y.Bus.GetAddress

which returns:

  Error org.freedesktop.DBus.Error.Spawn.ChildExited: Process org.a11y.Bus exited with status 1

This suggests that the session bus is running sufficiently to accept a
connection, but then something fails - any clues on how to find out what?

Possible clue from at-spi2-core/registryd/testregistry.py?

$ python3.3 testregistry.py 
  File "testregistry.py", line 38
    print apps
             ^
SyntaxError: invalid syntax
$ python2.7 testregistry.py
Traceback (most recent call last):
  File "testregistry.py", line 59, in <module>
    sys.exit(main(sys.argv))
  File "testregistry.py", line 48, in main
    introspect=False)
  File "/usr/pkg/lib/python2.7/site-packages/dbus/bus.py", line 241, in get_object
    follow_name_owner_changes=follow_name_owner_changes)
  File "/usr/pkg/lib/python2.7/site-packages/dbus/proxies.py", line 248, in __init__
    self._named_service = conn.activate_name_owner(bus_name)
  File "/usr/pkg/lib/python2.7/site-packages/dbus/bus.py", line 180, in activate_name_owner
    self.start_service_by_name(bus_name)
  File "/usr/pkg/lib/python2.7/site-packages/dbus/bus.py", line 278, in start_service_by_name
    'su', (bus_name, flags)))
  File "/usr/pkg/lib/python2.7/site-packages/dbus/connection.py", line 651, in call_blocking
    message, timeout)
dbus.exceptions.DBusException: org.freedesktop.DBus.Error.Spawn.ChildExited: Process org.a11y.Bus exited 
with status 1

The above was with glib 2.40.0. Downgrading to 2.38.2 gives me a working
at-spi2-registryd, and

$ python2.7 testregistry.py 
dbus.Array([], signature=dbus.Signature('(so)'))
$

Much happier...

Cheers,

Patrick


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