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Re: [xml] Reading CDATA
- From: Daniel Veillard <veillard redhat com>
- To: Hartmut Sbosny <hartmut sbosny gmx de>
- Cc: xml gnome org
- Subject: Re: [xml] Reading CDATA
- Date: Fri, 26 Sep 2008 11:15:36 +0200
On Fri, Sep 26, 2008 at 10:31:36AM +0200, Hartmut Sbosny wrote:
> Hi Daniel,
>
> On Thursday, 25. September 2008 17:05, Daniel Veillard wrote:
> > On Wed, Sep 17, 2008 at 06:48:37PM +0200, Hartmut Sbosny wrote:
> > > Hello,
> > > I am fresh to libxml. I want to read an xml file containing
> > > the part
> > > <data>
> > > <![CDATA[...]]>
> > > </data>
> > >
> > > Currently I use the xmlParseDoc() interface. My first try was to read the
> > > <data> node string via xmlNodeListGetString(). This returns something
> >
> > You just can't using that API.
>
> Is this a principle limitation of the xmlParseDoc API or only an
> accidental API lack? Which API is suitable to read cdata? Sorry for my
> stumbling asking, I am new to libxml and xml.
No API lack. You use an API to dump the content of a LIST of node
when you want the content of a SINGLE node.
There is a zillion ways to get it like accessing directly the
node->content pointer or using the API getting the content of
a single node like xmlNodeGetContent()
> > wei:~/XML -> xmllint --debug tst.xml
> > DOCUMENT
> > version=1.0
> > URL=tst.xml
> > standalone=true
> > ELEMENT data
> > TEXT compact
> > content=
> > CDATA_SECTION
> > content=...
> > TEXT compact
> > content=
> > wei:~/XML ->
> >
> > navigate in the tree and grab the data as content-> from the second
> > child of your containing element
>
> I probably miss the point. Do you mean I should use the command line
> tool 'xmllint'?
Hum, no I just tried to get you to understadn that the data model is
a tree and you need to walk that tree ... and xmllint --debug is a
convenient way to see this tree.
Daniel
--
Daniel Veillard | libxml Gnome XML XSLT toolkit http://xmlsoft.org/
daniel veillard com | Rpmfind RPM search engine http://rpmfind.net/
http://veillard.com/ | virtualization library http://libvirt.org/
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