Re: [xml] Setting a context from a patricular node

[eric_w <rice cruft gmail com>]

Doesn't this sequence

     doc = xmlTextReaderCurrentDoc( reader);
     pathContext = xmlXPathNewContext( doc);

accomplish the same thing? Or are you suggesting that is is sufficient to
just set the xmlNodePtr
in the path context structure?

  --Eric "still learning about the libxml2 apis" W


James Dennett-3 wrote:
> 
>> -----Original Message-----
>> From: xml-bounces gnome org [mailto:xml-bounces gnome org] On Behalf
> Of
>> Abhishek Jain
>> Sent: Wednesday, November 07, 2007 3:22 PM
>> To: xml gnome org
>> Subject: [xml] Setting a context from a patricular node
>> 
>> Hi,
>> 
>> I want to set the xmlXPathContext from a particular node say
> xmlNodePtr
>> node1 in a xmlDocPtr doc so that my XPath is evaluated in the subtree
> of
>> node1.
>> 
>> Please let me know how can i do that.
> 
> While I'd be more comfortable if I could find this documented, so far as
> I can tell the recommended approach is to set the "node" field of the
> xmlXPathContext, i.e., context->node = node1; in your case.
> 
> I'd also note that some library calls will change the node, so you
> should reset it before reusing a context.
> 
> -- James
> 
> _______________________________________________
> xml mailing list, project page  http://xmlsoft.org/
> xml gnome org
> http://mail.gnome.org/mailman/listinfo/xml
> 
> 

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