RE: [xml] Problem with xmlGetNodePath() and default namespaces

["Buchcik, Kasimier" <k buchcik 4commerce de>]

Hi,

Or, if we want to avoid a new function, and changing the current
behaviour of xmlGetNodePath() is OK, then we could let this
function generate "*[3]" steps for elements in the default
namespace, and keep the rest as is.

Regards,

Kasimier

> -----Original Message-----
> From: xml-bounces gnome org [mailto:xml-bounces gnome org] On 
> Behalf Of Buchcik, Kasimier
> Sent: Thursday, June 08, 2006 5:05 PM
> To: xml gnome org
> Subject: [xml] Problem with xmlGetNodePath() and default namespaces
> 
> Hi,
> 
> xmlGetNodePath() (tree.c) will return "/foo" for the
> following scenario:
> 
> <?xml version="1.0"?>
> <foo xmlns="urn:test:foo"/>
> 
> In this case, the result of xmlGetNodePath() is not suitable
> for usage as an expression in further XPath processing.
> 
> Is it OK to add to tree.c an other function which would generate
> a more generic path, without any information about node-names or
> namespaces?
> The result would be "/*"; and analogous for attributes, e.g.
> "/*/*[3]/@*[5]".
> 
> Regards,
> 
> Kasimier